10k^2+38k-8=0

Solution for 10k^2+38k-8=0 equation:

10k^2+38k-8=0

a = 10; b = 38; c = -8;
Δ = b2-4ac
Δ = 382-4·10·(-8)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-42}{2*10}=\frac{-80}{20}
=-4
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+42}{2*10}=\frac{4}{20}
=1/5
$